Видео ютуба по тегу Science Beta Jee Math Solved

JEE 2024 PYQ | Подсказка для определения целочисленной бета-функции! #jeemains #jeeadvanced
JEE 2024 PYQ | Подсказка для определения целочисленной бета-функции! #jeemains #jeeadvanced
18 December 2025
18 December 2025
High-Value JEE Variant: Cramer’s Rule + 3D Concepts for Zero, Unique & Infinite Solutions | #jee
High-Value JEE Variant: Cramer’s Rule + 3D Concepts for Zero, Unique & Infinite Solutions | #jee
Beta Functions | JEE Advanced | Integration | Olympiads | MATHS
Beta Functions | JEE Advanced | Integration | Olympiads | MATHS
Q) Let 𝛽=lim(𝑥→0) (𝛼𝑥−(𝑒^3𝑥−1))/𝛼𝑥(𝑒^3𝑥−1) for some 𝛼∈ℝ. Then the value of 𝛼+𝛽 in
Q) Let 𝛽=lim(𝑥→0) (𝛼𝑥−(𝑒^3𝑥−1))/𝛼𝑥(𝑒^3𝑥−1) for some 𝛼∈ℝ. Then the value of 𝛼+𝛽 in
Road to Math Olympiad Q7 #ioqm #inmo #jee #jeemains #iit #iitroorkee
Road to Math Olympiad Q7 #ioqm #inmo #jee #jeemains #iit #iitroorkee
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+
Q) If the points with vectors 𝛼𝑖 +10𝑗 +13𝑘 , 6𝑖 +11𝑗 +11𝑘 , 9/2 𝑖 +𝛽𝑗 −8𝑘 are collinear, then (19𝛼−
Q) If the points with vectors 𝛼𝑖 +10𝑗 +13𝑘 , 6𝑖 +11𝑗 +11𝑘 , 9/2 𝑖 +𝛽𝑗 −8𝑘 are collinear, then (19𝛼−
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+
Q) Let 𝛼 and 𝛽 be the roots of 𝑥^2+√3 𝑥−16=0, and 𝛾 and 𝛿 be the roots of 𝑥^2+3𝑥−1=0. If 𝑃_𝑛=𝛼^𝑛+𝛽
Q) Let 𝛼 and 𝛽 be the roots of 𝑥^2+√3 𝑥−16=0, and 𝛾 and 𝛿 be the roots of 𝑥^2+3𝑥−1=0. If 𝑃_𝑛=𝛼^𝑛+𝛽
Q) Let, a, ẞ be the distinct roots of the equation x²-(t^2 - 5t + 6)x + 1 = 0 and an = a^n + β^n.
Q) Let, a, ẞ be the distinct roots of the equation x²-(t^2 - 5t + 6)x + 1 = 0 and an = a^n + β^n.
Let 𝛼 and 𝛽 be the roots of x^2 - 6x-2=0. If an = a^n - ẞ^n for n≥ 1, then the value of a10 -
Let 𝛼 and 𝛽 be the roots of x^2 - 6x-2=0. If an = a^n - ẞ^n for n≥ 1, then the value of a10 -
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/
Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/
Q) If for some 𝛼,𝛽;𝛼≤𝛽, 𝛼+𝛽=8 and sec^2 (tan^(−1) 𝛼)+cos^2 (cot^(−1) 𝛽)=36, then 𝛼^2+𝛽 i
Q) If for some 𝛼,𝛽;𝛼≤𝛽, 𝛼+𝛽=8 and sec^2 (tan^(−1) 𝛼)+cos^2 (cot^(−1) 𝛽)=36, then 𝛼^2+𝛽 i
📘 JEE Main 2020 | (06 Sep Shift 2) | quadratic equation | Maths With Vishal#shorts
📘 JEE Main 2020 | (06 Sep Shift 2) | quadratic equation | Maths With Vishal#shorts
JEE Main 2021 | Advanced Integration Question Solved In 30 Sec | Maths With Vishal#shorts
JEE Main 2021 | Advanced Integration Question Solved In 30 Sec | Maths With Vishal#shorts
JEE Main 2021 | Advanced Integration Question Solved In 30 Sec | Maths With Vishal
JEE Main 2021 | Advanced Integration Question Solved In 30 Sec | Maths With Vishal
99.7% Failed to solve this JEE Advanced question
99.7% Failed to solve this JEE Advanced question
Q) Let 𝐴 be a matrix of order 3×3 and |𝐴|=5. If |2adj(3Aadj(2A))|= 2^𝛼 3^𝛽 5^𝛾,then 𝛼+𝛽+𝛾
Q) Let 𝐴 be a matrix of order 3×3 and |𝐴|=5. If |2adj(3Aadj(2A))|= 2^𝛼 3^𝛽 5^𝛾,then 𝛼+𝛽+𝛾
Q) If the domain of the 𝑓(𝑥)=cos^(−1) ((2−|𝑥|)/4)+ {log_𝑒 (3−𝑥)}^(−1) is [−𝛼,𝛽)−{𝛾}, then 𝛼+𝛽+𝛾
Q) If the domain of the 𝑓(𝑥)=cos^(−1) ((2−|𝑥|)/4)+ {log_𝑒 (3−𝑥)}^(−1) is [−𝛼,𝛽)−{𝛾}, then 𝛼+𝛽+𝛾
Q) If the domain of the function 𝑓(𝑥)=sin^(−1) ((𝑥−1)/(2𝑥+3)) is 𝑅−(𝛼,𝛽) then 12𝛼𝛽 is
Q) If the domain of the function 𝑓(𝑥)=sin^(−1) ((𝑥−1)/(2𝑥+3)) is 𝑅−(𝛼,𝛽) then 12𝛼𝛽 is
Q) If for some 𝛼,𝛽;𝛼≤𝛽, 𝛼+𝛽=8 and sec^2 (tan^(−1) 𝛼)+cos^2 (cot^(−1) 𝛽)=36, then 𝛼^2+𝛽 i
Q) If for some 𝛼,𝛽;𝛼≤𝛽, 𝛼+𝛽=8 and sec^2 (tan^(−1) 𝛼)+cos^2 (cot^(−1) 𝛽)=36, then 𝛼^2+𝛽 i
Gamma and Beta Functions Explained | JEE Advanced & IIT JAM Maths Made Easy
Gamma and Beta Functions Explained | JEE Advanced & IIT JAM Maths Made Easy
🔥 JEE Advanced 2025 | Ye Advanced Hai Beta – Darr Gaye to Ghar Gaye!
🔥 JEE Advanced 2025 | Ye Advanced Hai Beta – Darr Gaye to Ghar Gaye!" 💥 | NS SIR | #jeeadvanced2025
MIT Integration Bee Qualifying exam 2025 #calculus #integration #jee #gcse #science #iitjee #iit
MIT Integration Bee Qualifying exam 2025 #calculus #integration #jee #gcse #science #iitjee #iit